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3) Convert 40∘C an the
a) Fahrenheit scale
b) Kelvin scale
aF−32=5C9F−32=54089F−32=18F−32=9×8F−32=72F=72+32F=104∴40∘C=104∘F.
Video solution 1: 3) Convert 40∘C an the
a) Fahrenheit scale
b) Kelvin scale
aF−32=5C9F−32=54089F−32=18F−32=9×8F−32=72F=72+32F=104∴40∘C=104∘F.
A different of temperature of 25^(@)C is equivalent to a difference of
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